Two closed organ pipes of length $100 \,cm$ and $101 \,cm$ $16$ beats in $20\, sec$. When each pipe is sounded in its fundamental mode calculate the velocity of sound .... $ms^{-1}$
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(c) Number of beats per second,
$n = \frac{{16}}{{20}} = \frac{4}{5}$
==>$n = {n_1} - {n_2} = \frac{v}{4}\left( {\frac{1}{{{l_1}}} - \frac{1}{{{l_2}}}} \right)$
==>$\frac{4}{5} = \frac{v}{4}\left( {\frac{1}{1} - \frac{1}{{1.01}}} \right) = \frac{{0.01v}}{{4 \times 1.01}}$
$v = \frac{{16 \times 101}}{5} = 323.2\,m{s^{ - 1}}$
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