Two coils have a mutual inductance 0.005 ,H . The current changes… - Vidyadip

MCQ

Two coils have a mutual inductance $0.005\,H$ . The current changes in the first coil The current changes in the first coil according to the equation $I = I_0 sin\,\omega t$ , where $I_0 = 10\,A$ and $\omega = 100\pi \,rad/s$ . The maximum value of $emf$ in the second coil will be

✓
$5\pi $
B
$10\pi $
C
$2.5\pi $
D
$15\pi $

✓

Answer

Correct option: A.

$5\pi $

a
As, $|\varepsilon|=M \frac{d I}{d t}$

$=M \frac{d}{d t}\left(I_{0} \sin \omega t\right)=M I_{0} \omega \cos \omega t$

$\therefore \quad \varepsilon_{\max }=0.005 \times 10 \times 100 \pi \times 1=5 \pi$

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