MCQ
Two coins are tossed simultaneously. What is the probability of getting at most one head?
- A$\frac{1}{4}$
- B$\frac{1}{2}$
- C$\frac{2}{3}$
- ✓$\frac{3}{4}$
✓
Answer
Correct option: D.
$\frac{3}{4}$
When two coins are tossed the simultanecusly the
outcomes are :
$\text{\{HH, HT, TH, TT}\}$
So, there are $4$ outcomes.
Getting atmost one head means the possible outcomes are :
$\text{\{HT, TH, TT\}}$
So, there are $3$ possible outcomes.
$P($getting atmost one head$)$
$=\frac{3}{4}$
outcomes are :
$\text{\{HH, HT, TH, TT}\}$
So, there are $4$ outcomes.
Getting atmost one head means the possible outcomes are :
$\text{\{HT, TH, TT\}}$
So, there are $3$ possible outcomes.
$P($getting atmost one head$)$
$=\frac{3}{4}$
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