Two concentric hollow metallic spheres of radii $r_1$ and $r_2 (r_1 > r_2)$ contain charges $q_1$ and $q_2$ respectively. The potential at a distance $x$ between $r_1$ and $r_2$ will be
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Potential at $\mathrm{P}$ due to $\mathrm{A}$ is

$\mathrm{V}_{1}=\frac{\mathrm{q}_{1}}{4 \pi \varepsilon_{0} \mathrm{r}_{1}}$

and due to $\mathrm{B}$ is

$\mathrm{V}_{2}=\frac{\mathrm{q}_{2}}{4 \pi \varepsilon_{0} \mathrm{x}}$

Net potential at $\mathrm{P}$

$\mathrm{V}=\mathrm{V}_{1}+\mathrm{V}_{2}=\frac{1}{4 \pi \varepsilon_{0}}\left(\frac{\mathrm{q}_{2}}{\mathrm{X}}+\frac{\mathrm{q}_{1}}{\mathrm{r}_{1}}\right)$

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