Two conductors are made of the same material and have the same length. Conductor A is a solid wire of diameter 1.0, mm. Conductor B

Q: Two conductors are made of the same material and have the same length. Conductor $A$ is a solid wire of diameter $1.0\, mm$. Conductor $B$ is a hollow tube of outside diameter $2.0\, mm$ and inside diameter $1.0\, mm$. The resistance ratio $R_A/R_B$ will be

c For conductor $A$, ${R_A} = \frac{{\rho \,l}}{{\pi r_1^2}}$, For conductor $B$, ${R_B} = \frac{{\rho \,l}}{{\pi (r_2^2 - r_1^2)}}$ $ \Rightarrow $ $\frac{{{R_A}}}{{{R_B}}} = \frac{{r_2^2 - r_1^2}}{{r_1^2}} = {\left( {\frac{{{r_2}}}{{{r_1}}}} \right)^2} - 1 = {\left( {\frac{{{d_2}}}{{{d_1}}}} \right)^2} - 1 = {\left( {\frac{2}{1}} \right)^2} - 1 = 3$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Two conductors are made of the same material and have the same length. Conductor $A$ is a solid wire of diameter $1.0\, mm$. Conductor $B$ is a hollow tube of outside diameter $2.0\, mm$ and inside diameter $1.0\, mm$. The resistance ratio $R_A/R_B$ will be

A$1$
B$2$
C$3$
D$4$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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