MCQ
Two dice are rolled simultaneously. The probability that they show different faces is:
- A$\frac{2}{3}$
- B$\frac{1}{6}$
- C$\frac{1}{3}$
- ✓$\frac{5}{6}$
✓
Answer
Correct option: D.
$\frac{5}{6}$
Two dice are rolled simultaneously
$\therefore$ No. of total events $= 6^2 = 36$
$\therefore$ No. of different face can be
$= 36 - ($ same faces$)$
Same face are $(1, 1), (2, 2), (3, 3), (4, 4), (5, 5)$ and ($6, 6) = 6$
$\therefore 36 - 6 = 30$
$\therefore\ \text{Probability P (E)}=\frac{\text{m}}{\text{n}}=\frac{30}{36}=\frac{5}{6}$
$\therefore$ No. of total events $= 6^2 = 36$
$\therefore$ No. of different face can be
$= 36 - ($ same faces$)$
Same face are $(1, 1), (2, 2), (3, 3), (4, 4), (5, 5)$ and ($6, 6) = 6$
$\therefore 36 - 6 = 30$
$\therefore\ \text{Probability P (E)}=\frac{\text{m}}{\text{n}}=\frac{30}{36}=\frac{5}{6}$
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