MCQ
Two equal masses $m$ and $m$ are hung from a balance whose scale pans differ in vertical height by $'h'$. The error in weighing in terms of density of the earth $\rho $ is
  • A
    $\pi G\rho mh$
  • B
    $\frac{1}{3}\pi G\rho mh$
  • $\frac{8}{3}\pi G\rho mh$
  • D
    $\frac{4}{3}\pi G\rho mh$

Answer

Correct option: C.
$\frac{8}{3}\pi G\rho mh$
c
$\mathrm{g}_{1}=\frac{\mathrm{g}}{\left[1+\frac{\mathrm{h}}{\mathrm{R}}\right]^{2}}=\mathrm{g}\left[1-\frac{2 \mathrm{h}}{\mathrm{R}}\right]$

$\mathrm{W}_{2}-\mathrm{W}_{1}=\mathrm{mg}_{2}-\mathrm{mg}_{1}$

$=2 \mathrm{mg}\left[\frac{\mathrm{h}_{1}}{\mathrm{R}}-\frac{\mathrm{h}_{2}}{\mathrm{R}}\right]=2 \mathrm{m} \frac{\mathrm{GM}}{\mathrm{R}^{2}} \frac{\mathrm{h}}{\mathrm{R}}$

$\left[\because \mathrm{g}=\frac{\mathrm{GM}}{\mathrm{R}^{2}} \text { and } \mathrm{h}_{1}-\mathrm{h}_{2}=\mathrm{h}\right]$

$\therefore \mathrm{W}_{2}-\mathrm{W}_{1}=$ error in weighing

$=2 \mathrm{mG} \cdot \frac{4}{3} \pi \mathrm{R}^{3} \rho \frac{\mathrm{h}}{\mathrm{R}^{3}}=\frac{8 \pi}{3} \mathrm{Gm} \rho \mathrm{h}$

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