Two free parallel wires carrying currents in opposite direction
Easy
Download our app for free and get started
(b) Two wires, if carries current in opposite direction, they repel each other.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A rectangular region $A B C D$ contains a uniform magnetic field $B_0$ directed perpendicular to the plane of the rectangle. A narrow stream of charged particles moving perpendicularly to the side $AB$ enters this region and is ejected through the adjacent side $B C$ suffering a deflection through $30^{\circ}$. In order to increase this deflection to $60^{\circ}$, the magnetic field has to be
A voltmeter has a resistance of $G\, ohms$ and range $V\, volts$. The value of resistance used in series to convert it into a voltmeter of range $nV$ $volts$ is
An ammeter whose resistance is $180\,\Omega $ gives full scale deflection when current is $2\, mA$. The shunt required to convert it into an ammeter reading $20\, mA$ (in $ohms$) is
For the magnetic field to be maximum due to a small element of current carrying conductor at a point, the angle between the element and the line joining the element to the given point must be.......$^o$
Which one of the following options represents the magnetic field $\vec{B}$ at $O$ due to the current flowing in the given wire segments lying on the $x y$ plane?
A tightly wound $100$ turns coil of radius $10 \mathrm{~cm}$ carries a current of $7 \mathrm{~A}$. The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4 \pi \times 10^{-7} \mathrm{SI}$ units):
A galvanometer of $50\, ohm$ resistance has $25$ divisions. A current of $4 \times 10^{-4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of $25\, volts$, it should be connected with a resistance of