MCQ
Two full turns of the circular scale of screw gauge cover a distance of $1\,mm$ on scale. The total number of divisions on circular scale is $50$. Further, it is found that screw gauge has a zero error of $+0.03\,mm$. While measuring the diameter of a thin wire a student notes the main scale reading of $3\,mm$ and the number of circular scale division in line, with the main scale is $35$. The diameter of the wire is .......... $mm$
  • $3.32$
  • B
    $3.73$
  • C
    $3.67$
  • D
    $3.38$

Answer

Correct option: A.
$3.32$
a
pitch $=\frac{1 \mathrm{mm}}{2}=0.5 \mathrm{mm}$

$\mathrm{LC}=\frac{0.5 \mathrm{mm}}{50}=0.01 \mathrm{mm}$

observed diameter

${=3 \mathrm{mm}+(35 \times 0.01 \mathrm{mm})}$

${=3.35 \mathrm{mm}}$

Actual diameter

$= observed - error$

$=3.35 \mathrm{mm}-(+0.03 \mathrm{mm})$

$=3.32 \mathrm{\,mm}$

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