Question
Two identical blocks of mass 2 kg move towards each other with a uniform speed ( $2 m / s$ ) on a frictionless horizontal plane. They collide with each other and get attached to each other and comes to a state of rest. Calculate the work done by external forces and internal forces on the system of both the particles.

Answer

Since there is no external force acting on the blocks.
$\therefore$ Work done by external forces $=0$
Kinetic energy before the collision of two block
$=\frac{1}{2} \times 2 \times(2)^2+\frac{1}{2} \times 2 \times(2)^2$
$=4+4=8 J$
On collision both blocks are attaches and comes to a state of rest. Hence their total energy will be zero.
$\therefore$ Work done by internal forces
$\begin{array}{l}
=k_{f}-k_{i} \\
=0-8=-8 J \quad Ans.
\end{array}$

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