Two identical capacitors are joined in parallel, charged to a potential $V$ and then separated and then connected in series $i.e.$ the positive plate of one is connected to negative of the other
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(d) ${Q_1} = CV$ and ${Q_2} = CV$
Applying charge conservation $C{V_1} + C{V_2} = {Q_1} + {Q_2}$
$C{V_1} + C{V_2} = 2CV$ $==>$ ${V_1} + {V_2} = 2\,V$
Applying charge conservation $C{V_1} + C{V_2} = {Q_1} + {Q_2}$
$C{V_1} + C{V_2} = 2CV$ $==>$ ${V_1} + {V_2} = 2\,V$
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