Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_1$ and the other to $V_2$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is
  • A$\frac{1}{4}C\left( {V_1^2 - V_2^2} \right)$
  • B$\frac{1}{4}C\left( {V_1^2 + V_2^2} \right)$
  • C$\frac{1}{4}C{\left( {{V_1} - {V_2}} \right)^2}$
  • D$\frac{1}{4}C{\left( {{V_1} + {V_2}} \right)^2}$
Medium
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