Two identical harmonic pulses travelling in opposite directions in a taut string approach each other. At the instant when they completely overlap, the total energy of the string will be
Easy
Download our app for free and get started
When they overlap, they form stationary waves, as they cancel each other because of the opposite direction and equal magnitude.
Hence the displacement of the string becomes zero, resulting in zero potential energy and purely kinetic energy.
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionSound waves of wavelength greater than that of audible sound are called
- 2View SolutionAn empty vessel is partially filled with water, then the frequency of vibration of air column in the vessel
- 3A tuning fork of frequency $340Hz$ is vibrated just above the tube of $120 cm$ height. Water is poured slowly in the tube. What is the minimum height of water necessary for the resonance .... $cm$ (speed of sound in the air $= 340 m/sec$)View Solution
- 4The wavelength of a particle is $99 cm$ and that of other is $100 cm$ Speed of sound is $396 m/s$. The number of beats heard isView Solution
- 5In a resonance tube the first resonance with a tuning fork occurs at $16 cm$ and second at $49 cm.$ If the velocity of sound is $330 m/s,$ the frequency of tuning fork isView Solution
- 6A resonance air column of length $20 cm$ resonates with a tuning fork of frequency $250 Hz$. The speed of sound in air is .... $m/s$View Solution
- 7If the fundamental frequency of string is $220 \,cps$, the frequency of fifth harmonic will be ......... $cps$View Solution
- 8Two close organ pipe having length $20\,cm$ and $20.5\, cm$ produce $5\, beats/sec$. Determine the frequency of both organ pipeView Solution
- 9A tuning fork of frequency $340\,\, Hz$ is vibrated just above a cylindrical tube of length $120 \,\,cm$. Water is slowly poured in the tube. If the speed of sound is $340\,\, ms^{-1}$ then the minimum height of water required for resonance is .... $cm$View Solution
- 10The transverse displacement $y (x, t)$ of a wave on a string is given by $y\left( {x,t} \right) = {e^{ - \left( {a{x^2} + b{t^2} + 2\sqrt {ab} \;xt} \right)}}$ .This represents aView Solution