Two identical heater filaments are connected first in parallel and then in series. At the same applied voltage, the ratio of heat produced in same time for parallel to series will be:
JEE MAIN 2023, Medium
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Parallel combination
$H _{ p }=\left[\frac{ V ^2}{\left(\frac{ R }{2}\right)}\right) t =\frac{2 V ^2 t }{ R }$
Series combination
$H _s=\left(\frac{ V ^2}{2 R }\right) t \quad \therefore \frac{ H _{ p }}{ H _{ s }}=4$
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