Two liquids of densities $\rho_{1}$ and $\rho_{2}\left(\rho_{2}=2 \rho_{1}\right)$ are filled up behind a square wall of side $10\; \mathrm{m}$ as shown in figure. Each liquid has a height of $5 \;\mathrm{m} .$ The ratio of the forces due to these liquids exerted on upper part $MN$ to that at the lower pait $NO$ is (Assume that the liquids are not mixing)
JEE MAIN 2020, Medium
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$\mathrm{F}_{1}=\frac{\rho \mathrm{gh}}{2} \times \mathrm{A}$
$\mathrm{F}_{2}=\left(\rho \mathrm{gh}+\frac{2 \rho \mathrm{gh}}{2}\right) \mathrm{A}$
$\frac{\mathrm{F}_{1}}{\mathrm{F}_{2}}=\frac{1}{4}$
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