Two long conductors, separated by a distance $d$ carry current $I_1$ and $I_2$ in the same direction. They exert a force $F$ on each other. Now the current in one of them is increased to two times and its directions is reversed. The distance is also increased to $3d$. The new value of the force between them is
A$-2F$
B$F/3$
C$2F/3$
D$-F/3$
AIEEE 2004, Medium
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C$2F/3$
c (c) $F \propto \frac{{{i_1}{i_2}}}{a}$; Since one of the current increase two times and distance increases three times, so force become $\frac{2}{3}$times. Also due to the reversal of direction of current force becomes negative.
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