MCQ
Two long conductors, separated by a distance $d$ carry current $I_1$ and $I_2$ in the same direction. They exert a force $F$ on each other. Now the current in one of them is increased to two times and its directions is reversed. The distance is also increased to $3d$. The new value of the force between them is
  • A
    $-2F$
  • B
    $F/3$
  • $2F/3$
  • D
    $-F/3$

Answer

Correct option: C.
$2F/3$
c
(c) $F \propto \frac{{{i_1}{i_2}}}{a}$; Since one of the current increase two times and distance increases three times, so force become $\frac{2}{3}$times. Also due to the reversal of direction of current force becomes negative.

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