Two long straight wires $P$ and $Q$ carrying equal current $10\,A$ each were kept parallel to each other at $5\,cm$ distance. Magnitude of magnetic force experienced by $10\,cm$ length of wire $P$ is $F_1$. If distance between wires is halved and currents on them are doubled, force $F_2$ on $10\,cm$ length of wire $P$ will be :
  • A$8 F_1$
  • B$10 F_1$
  • C$F_1 / 8$
  • D$F_1 / 10$
JEE MAIN 2023, Medium
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