Two moles of helium gas are taken over the cycle $ABCDA$, as shown in the $P-T$ diagram. The net work done on the gas in the cycle $ABCDA$ is ...... $R$
AIEEE 2009, Medium
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The net work in the cycle $ABCDA$ is
$W = {W_{AB}} + {W_{BC}} + {W_{CD}} + {W_{DA}}$
$ = 400R + 2.303nRT\log \frac{{{P_B}}}{{{P_C}}} + \left( { - 400R} \right) - 414R$
$ = 2.303 \times 2R \times 500\log \frac{{2 \times {{10}^5}}}{{1 \times {{10}^5}}} - 414R$
$ = 693.2\,R - 414\,R = 279.2\,R$
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