Question
Two particles A and B have a phase difference of $\pi$ when a sine wave passes through the region.
  1. A oscillates at half the frequency of B.
  2. A and B move in opposite directions.
  3. A and B must be separated by half of the wavelength.
  4. The displacements at A and B have equal magnitudes.

Answer

  1. A and B move in opposite directions.
  1. The displacements at A and B have equal magnitudes.
Explanation:

A and Bhave a phase difference of fl. So, when a sine wave passes through the region, they move in opposite directions and have equal displacement. They may be separated by any odd multiple of their wavelength.
$\overrightarrow{\text{yA}}=\text{A}\sin(\omega\text{t})$
$\overrightarrow{\text{yB}}=\text{B}\sin(\omega\text{t}+\pi)$

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