Two particles $A$ and $B$ of equal masses are suspended from two massless springs of spring constants $K _{1}$ and $K _{2}$ respectively.If the maximum velocities during oscillations are equal, the ratio of the amplitude of $A$ and $B$ is
JEE MAIN 2021, Medium
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$A _{1} \omega_{1}= A _{2} \omega_{2}$
$A_{1} \sqrt{\frac{k_{1}}{m}}=A_{2} \sqrt{\frac{k_{2}}{m}}$
$\frac{ A _{1}}{ A _{2}}=\sqrt{\frac{ k _{2}}{ k _{1}}}$
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