A $LCR$ circuit behaves like a damped harmonic oscillator. Comparing it with a physical springmass damped oscillator having damping constant $\mathrm{b}$, the correct equivalence would be:
JEE MAIN 2020, Diffcult
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By $kVL$
$-\mathrm{L} \frac{\mathrm{di}}{\mathrm{dt}}-\frac{\mathrm{q}}{\mathrm{C}}-\mathrm{iR}=0$
$\mathrm{L} \frac{\mathrm{d}^{2} \mathrm{q}}{\mathrm{dt}^{2}}+\frac{1}{\mathrm{C}} \mathrm{q}+\mathrm{R} \frac{\mathrm{dq}}{\mathrm{dt}}=0$
for damped oscillator
net force $=-\mathrm{kx}-\mathrm{bv}=\mathrm{ma}$
$\frac{m d^{2} x}{d t^{2}}+k x+\frac{b d x}{d t}=0$
by comparing : Equivalence is
$\mathrm{L} \rightarrow \mathrm{m}: \mathrm{C} \rightarrow \frac{1}{\mathrm{K}} ; \mathrm{R} \rightarrow \mathrm{b}$
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