Two particles are executing simple harmonic motion of the same am… - Vidyadip

MCQ

Two particles are executing simple harmonic motion of the same amplitude $A$ and frequency $\omega $ along the $x-$ axis. Their mean position is separated by distance $X_0 (X_0> A)$. If the maximum separation between them is $(X_0 +A)$, the phase difference between their motion is

A
$\frac{\pi }{6}$
✓
$\frac{\pi }{2}$
C
$\frac{\pi }{3}$
D
$\frac{\pi }{4}$

✓

Answer

Correct option: B.

$\frac{\pi }{2}$

b
At extreme position, phase difference $=\frac{\pi }{2}$

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