Two particles are in $SHM$ in a straight line. Amplitude $A$ and time period $T$ of both the particles are equal. At time $t=0,$ one particle is at displacement $y_1= +A$ and the other at $y_2= -A/2,$ and they are approaching towards each other. After what time they cross each other ?
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Angle covered to meet $\theta=60^{\circ}=\frac{\pi}{3} \mathrm{rad}$
If they cross each other at time $t$ then
$\mathrm{t}=\frac{\theta}{2 \pi}=\frac{\pi}{3 \times 2 \pi} \mathrm{T}=\frac{\mathrm{T}}{6}$
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