Two particles are in SHM on same straight line with amplitude A a… - Vidyadip

MCQ

Two particles are in $SHM$ on same straight line with amplitude $A$ and $2A$ and with same angular frequency $\omega .$ It is observed that when first particle is at a distance $A/\sqrt{2}$ from origin and going toward mean position, other particle is at extreme position on other side of mean position. Find phase difference between the two particles

A
$45^o$
B
$90^o$
✓
$135^o$
D
$180^o$

✓

Answer

Correct option: C.

$135^o$

c
Consider $2$ circles with radii $A \& 2 A$ and particles moving on them with constant angular velocity $\omega$

Choose $x$ axis to be horizontal on which the projection of the particles are to be taken.

When the projection of the first particle is at a distance $A / \sqrt{2}$ from origin, it is at an angle $45^{0}$ in the first quadrant.

whereas the second particle is at an angle $180^{0}$.

i.e the phase difference is $135^{0}$

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