The elongation of a wire on the surface of the earth is $10^{-4} \; m$. The same wire of same dimensions is elongated by $6 \times 10^{-5} \; m$ on another planet. The acceleration due to gravity on the planet will be $\dots \; ms ^{-2}$. (Take acceleration due to gravity on the surface of earth $=10 \; m / s ^{-2}$ )
JEE MAIN 2022, Medium
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$\Delta \ell \propto g$
$\frac{\Delta \ell_{\text {earth }}}{\Delta \ell_{\text {planet }}}=\frac{g_{\text {earth }}}{g_{\text {planet }}}=\frac{10^{-4}}{6 \times 10^{-5}}$
$g_{planet} = 6 \; m / s ^{-2}$
Ans. $6.00$
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