MCQ
Two plates are $2\,cm$ apart, a potential difference of $10\;volt$ is applied between them, the electric field between the plates is.........$N/C$
- A$20$
- ✓$500$
- C$5$
- D$250$
✓
Answer
Correct option: B.
$500$
b
(b) $E = \frac{V}{d} = \frac{{10}}{{2 \times {{10}^{ - 2}}}} = 500\,N/C$
(b) $E = \frac{V}{d} = \frac{{10}}{{2 \times {{10}^{ - 2}}}} = 500\,N/C$
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