MCQ
Two points $A$ and $B$ have coordinates $(1, 0)$ and $(-1, 0)$ respectively and $Q$ is a point which satisfies the relation $AQ - BQ = $ $ \pm 1.$The locus of $Q$ is
  • A
    $12{x^2} + 4{y^2} = 3$
  • $12{x^2} - 4{y^2} = 3$
  • C
    $12{x^2} - 4{y^2} + 3 = 0$
  • D
    $12{x^2} + 4{y^2} + 3 = 0$

Answer

Correct option: B.
$12{x^2} - 4{y^2} = 3$
b
(b) According to the given condition

$\sqrt {{{(x - 1)}^2} + {y^2}} - \sqrt {{{(x + 1)}^2} + {y^2}} = \pm 1$

On squaring both sides, we get

$2{x^2} + 2{y^2} + 1 = 2\sqrt {{{(x - 1)}^2} + {y^2}} .\sqrt {{{(x + 1)}^2} + {y^2}} $

Again on squaring, we get $12{x^2} - 4{y^2} = 3$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free