Two simple harmonic motions, as shown, are at right angles. They are combined to form Lissajous figures

$x\left( t \right) = A\,\sin \,\left( {at + \delta } \right)$

$y\left( t \right) = B\,\sin \,\left( {bt} \right)$

Identify the correct match below

JEE MAIN 2018, Diffcult
Download our app for free and get startedPlay store
From the two mutually perpendicular $S.H.M. 's$, the general equation of Lissajous figure

$\frac{{{x^2}}}{{{A^2}}} + \frac{{{y^2}}}{{{B^2}}} - \frac{{2xy}}{{AB}}\cos \,\delta  = {\sin ^2}\,\delta$ 

$x = A\,\sin \,\left( {at + \delta } \right)$

$y = B\,\sin \,\left( {bt + r} \right)$

Clearly $A\ne B$ hence ellipse

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A wooden cube (density of wood $'d'$ ) of side $'l'$ floats in a liquid of density $'\rho '$ with its upper and lower surfaces horizontal. If the cube is pushed slightly down and released, it performs simple harmonic motion of period $'T'$. Then, $'T'$ is equal to
    View Solution
  • 2
    At a given point of time the value of displacement of a simple harmonic oscillator is given as $y = A \cos \left(30^{\circ}\right)$. If amplitude is $40\,cm$ and kinetic energy at that time is $200\, J$, the value of force constant is $1.0 \times 10^{ x }\,Nm ^{-1}$. The value of $x$ is ......
    View Solution
  • 3
    A uniform thin ring of radius $R$ and mass $m$ suspended in a vertical plane from a point in its circumference. Its time period of oscillation is ........
    View Solution
  • 4
    A linear harmonic oscillator of force constant $2 \times {10^6}N/m$ and amplitude $0.01\, m$ has a total mechanical energy of $160$ joules. Its
    View Solution
  • 5
    An object of mass $0.5\, {kg}$ is executing simple harmonic motion. Its amplitude is $5\, {cm}$ and time period (T) is $0.2\, {s} .$ What will be the potential energy of the object at an instant $t=\frac{T}{4}$ s starting from mean position. Assume that the initial phase of the oscillation is zero. (In ${J}$)
    View Solution
  • 6
    A particle is excuting a simple harmonic motion. Its maximum acceleration is $\alpha $ and maximum velocity is $\beta $. Then its frequency of vibration will be
    View Solution
  • 7
    The maximum velocity of a simple harmonic motion represented by $y = 3\sin \,\left( {100\,t + \frac{\pi }{6}} \right)$is given by
    View Solution
  • 8
    A vibratory motion is represented by $x = 2\,A\,\cos \,\omega t + A\,\cos \,\left( {\omega t + \frac{\pi }{2}} \right) + A\,\cos \,\left( {\omega t + \pi } \right) + \frac{A}{2}\,\cos \,\left( {\omega t + \frac{{3\pi }}{2}} \right)$ The resultant amplitude of motion is
    View Solution
  • 9
    Two parallel discs are connected by a rigid rod of length $L=0.5 \,m$ centrally. Each disc has a slit oppositely placed as shown in the figure. A beam of neutral atoms are incident on one of the discs axially at different velocities $v$, while the system is rotated at angular speed of $600 \,rev / second$, so that atoms only with a specific velocity emerge at the other end. Calculate the two largest speeds (in metre/second) of the atoms that will emerge at the other end.
    View Solution
  • 10
    Two simple pendulums of length $1\, m$ and $4\, m$ respectively are both given small displacement in the same direction at the same instant. They will be again in phase after the shorter pendulum has completed number of oscillations equal to
    View Solution