A wooden cube (density of wood $'d'$ ) of side $'l'$ floats in a liquid of density $'\rho '$ with its upper and lower surfaces horizontal. If the cube is pushed slightly down and released, it performs simple harmonic motion of period $'T'$. Then, $'T'$ is equal to
AIEEE 2011, Diffcult
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By using $T=2 \pi \sqrt{\frac{m}{A \rho g}}$
Where $m=l^{3} d$ and $A=l^{2}$
$T=2 \pi \sqrt{\frac{l^{3} d}{l^{2} \rho g}} \Rightarrow T=2 \pi \sqrt{\frac{l d}{\rho g}}$
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