Two sound waves with wavelengths $5.0\,\, m$ and $5 .5\,\, m$ respectively, each propagate in a gas with velocity $330\,\, m/s.$ We expect the following number of beats per second.
AIPMT 2006, Medium
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Frequency $=\frac{\text { velocity }}{\text { wavelength }}$
$v_{1}=\frac{v}{\lambda_{1}}=\frac{330}{5}=66 \mathrm{Hz}$
and $v_{2}=\frac{v}{\lambda_{2}}=\frac{330}{5.5}=60 \mathrm{Hz}$
Number of beats per second $=v_{1}-v_{2}$
$=66-60=6$
$v_{1}=\frac{v}{\lambda_{1}}=\frac{330}{5}=66 \mathrm{Hz}$
and $v_{2}=\frac{v}{\lambda_{2}}=\frac{330}{5.5}=60 \mathrm{Hz}$
Number of beats per second $=v_{1}-v_{2}$
$=66-60=6$
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