Two square metal plates $A$ and $B$ are of the same thickness and material. The side of $B$ is twice that of $A$. These are connected as shown in series. If the resistances of $A$ and $B$ are denoted by $R_A$ and $R_B,$ then $(R_A/R_B)$ is
Medium
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$R_{A}=\rho \frac{\ell}{A}=\rho \frac{\ell}{\ell \times t} \quad R_{B}=\rho \frac{2 \ell}{2 \ell \times t}=\rho \frac{\ell}{\ell t}$
$\Rightarrow \mathrm{R}_{\mathrm{A}}=\mathrm{R}_{\mathrm{B}}$
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