${\mathrm{k}_{1} \tan \theta_{1}=\mathrm{K}_{2} \tan \theta_{2}}$
${\frac{\mathrm{k}_{1}}{\mathrm{k}_{2}}=\frac{\tan \theta_{2}}{\tan \theta_{1}}=\frac{1}{\sqrt{3}}}$
$\mathrm{k} \propto \frac{\mathrm{R}}{\mathrm{N}}$ (radius is same for both)
$\frac{\mathrm{K}_{1}}{\mathrm{K}_{2}}=\frac{\mathrm{N}_{2}}{\mathrm{N}_{1}}$
$\Rightarrow \frac{\mathrm{N}_{1}}{\mathrm{N}_{2}}=\frac{\mathrm{K}_{2}}{\mathrm{K}_{1}}=\frac{\sqrt{3}}{1}$
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(Surface tension of water $=0.075 N / m$, density of water $=1000 kg / m ^3$, take $g =10 m / s ^2$ )
$(1)$ The correction in the height of water column raised in the tube, due to weight of water contained in the meniscus, will be different for both cases.
$(2)$ For case I, if the capillary joint is $5 cm$ above the water surface, the height of water column raised in the tube will be more than $8.75 cm$. (Neglect the weight of the water in the meniscus)
$(3)$ For case $I$, if the joint is kept at $8 cm$ above the water surface, the height of water column in the tube will be $7.5 cm$. (Neglect the weight of the water in the meniscus)
$(4)$ For case II, if the capillary joint is $5 cm$ above the water surface, the height of water column raised in the tube will be $3.75 cm$. (Neglect the weight of the water in the meniscus)