Two tubes of radii $r_1$ and $r_2$, and lengths $l_1$ and $l_2$, respectively, are connected in series and a liquid flows through each of them in streamline conditions. $P_1$ and $P_2$ are pressure differences across the two tubes. If $P_2$ is $4P_1$ and $l_2$ is $ \frac{l_1}{4}$ , then the radius $r_2$ will be equal to
  • A$r_1$
  • B$2r_1$
  • C$4r_1$
  • D$\frac{r_1}{2}$
JEE MAIN 2017, Diffcult
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