Two vibrating tuning forks produce progressive waves given by ${Y_1} = 4\sin 500\pi t$ and ${Y_2} = 2\sin 506\pi t.$ Number of beats produced per minute is
A$360$
B$180$
C$3$
D$60$
AIPMT 2005, Medium
Download our app for free and get started
B$180$
b (b)From the given equations of progressive waves ${\omega _1} = 500\pi $ and ${\omega _2} = 506\pi $ ${n_1} = 250$ and ${n_2} = 253$
So beat frequency $ = {n_2} - {n_1} = 253 - 250 = 3$ beats per sec Number of beats per min = 180.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
At $23^{\circ} C$, a pipe open at both ends resonates at a frequency of $450 \,Hz$. At what frequency does the same pipe resonate on a hot day when the speed of sound is $4 \%$ higher than it would be at $23^{\circ} C$ ?
The equation of a travelling wave is $y = 60\cos (1800t - 6x)$ where $y$ is in microns, $t$ in seconds and $x$ in metres. The ratio of maximum particle velocity to velocity of wave propagation is
At a moment in a progressive wave, the phase of a particle executing $S.H.M.$ is $\frac{\pi }{3}$. Then the phase of the particle $15 cm$ ahead and at the time $\frac{T}{2}$ will be, if the wavelength is $60 cm$
A police car with a siren of frequency $8$ $kHz$ is moving with uniform velocity $36$ $km/hr$ towards a tall building which reflects the sound waves. The speed of sound in air is $320$ $m/s$. The frequency of the siren heard by the car driver is .... $kHz$
Two tuning forks $A$ and $B$ vibrating simultaneously produce $5$ beats. Frequency of $B$ is $512.$ It is seen that if one arm of $A$ is filed, then the number of beats increases. Frequency of $A$ will be
A string fixed at one end is vibrating in its second overtone. The length of the string is $10\ cm$ and maximum amplitude of vibration of particles of the string is $2\ mm$ . Then the amplitude of the particle at $9\ cm$ from the open end is