Two waves are represented by ${y_1} = a\sin \left( {\omega \,t + \frac{\pi }{6}} \right)$ and ${y_2} = a\cos \omega \,t$. What will be their resultant amplitude
A$a$
B$\sqrt 2 \,a$
C$\sqrt 3 \,a$
D$2a$
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C$\sqrt 3 \,a$
c (c) $A = \sqrt {(a_1^2 + a_2^2 + 2{a_1}{a_2}\cos \phi )} $
Putting ${a_1} = {a_2} = a$ and $\phi = \frac{\pi }{3}$, we get $A = \sqrt 3 a$
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