Two wires $A$ and $B$ are carrying currents $I_1$ and $I_2$ as shown in the figure. The separation between them is $d$. A third wire $C$ carrying a current $I$ is to be kept parallel to them at a distance $x$ from $A$ such that the net force acting on it is zero. The possible values of $x$ are
JEE MAIN 2019, Medium
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Net force on wire carrying current $I$ per unit length is
$\frac{\mu_{0} I_{1} I}{2 \pi x}+\frac{\mu_{0} I_{2} I}{2 \pi(d-x)}=0$
$\frac{I_{1}}{x}=\frac{I_{2}}{x-d}$
$\Rightarrow x=\frac{I_{1} d}{I_{1}-I_{2}}$
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