Two wires $A$ and $B$ of the same material, having radii in the ratio $1: 2$ carry currents in the ratio $4: 1$. The ratio of drift speed of electrons in $A$ and $B$ is
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(a)
$4 i=\text { neA } V_D$
$i=n e(4 A) V_D^{\prime }$
$4=\frac{V_D}{4 V_D^{\prime}}$
$\frac{V_D}{V_D^{\prime}}=16: 1$
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