
$T _2=20+11.4$
$=31.4\,N$
Elongation in steel wire $\Delta L =\frac{ T _2 L }{ Ay }$
$\Delta L =\frac{31.4 \times 1.6}{\pi\left(0.2 \times 10^{-2}\right)^2 \times 2 \times 10^{11}}$
$\Delta L =\frac{16}{2 \times 4 \times 10^{-5} \times 10^{11}}$
$=2 \times 10^{-5}\,m$
$=20 \times 10^{-6}\,m$
