Two wires of same diameter of the same material having the length $l$ and $2l.$ If the force $ F$ is applied on each, the ratio of the work done in the two wires will be
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(a)$W = \frac{1}{2}Fl$ $\therefore$ $W \propto l$ $(F$ is constant$)$
$\frac{{{W_1}}}{{{W_2}}} = \frac{{{l_1}}}{{{l_2}}} = \frac{l}{{2l}} = \frac{1}{2}$
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