A wire of length $50\, cm$ and cross sectional area of $1$ sq. mm is extended by $1\, mm.$ The required work will be      $(Y = 2 \times {10^{10}}\,N{m^{ - 2}})$
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(c) $W = \frac{{YA{l^2}}}{{2L}} = \frac{{2 \times {{10}^{10}} \times {{10}^{ - 6}} \times {{({{10}^{ - 3}})}^2}}}{{2 \times 50 \times {{10}^{ - 2}}}}$$ = 2 \times {10^{ - 2}}\;J$
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