$2PhCHO \xrightarrow{{:\mathop O\limits^ \ominus  H}}PhC{H_2}OH + PhC\mathop {O_2^ \ominus }\limits^{.\,\,.\,\,} $

ધીમો તબબકો  :

 $HC \equiv CH\mathop {\xrightarrow{{30\%\, {H_2}S{O_4}}}}\limits_{HgS{O_4}} A\xrightarrow{{NaOH}}B$

[જ્યાં, $\left.{Et} \Rightarrow-{C}_{2} {H}_{5}{ }^{{t}} {Bu} \Rightarrow\left({CH}_{3}\right)_{3} {C}-\right]$,

ઉપરોક્ત પ્રક્રિયા ક્રમનો વિચાર કરો, અનુક્રમે રચાયેલ નીપજ $"A"$ અને નીપજ $"B"$ છે:

$\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_2} = C - C{H_2} - C - C{H_3}} 
\end{array}}\limits_{(I)}  \rightleftharpoons $

$\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C - C{H_2} - C - C{H_3}} 
\end{array}}\limits_{(II)}  \rightleftharpoons $

$\mathop {\begin{array}{*{20}{c}}
  {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||} \\ 
  {C{H_3} - C = CH - C - C{H_3}} 
\end{array}}\limits_{(III)} $