(નજીકના પૂર્ણાંક સુધી રાઉન્ડ) [આપેલ : આણ્વિય દળ : $C =12.0 \,u , H : 1.0\, u,O : 16.0 \,u , Br =80.0 \,u ]$
$=$ moles of m-bromobenzoic acid
So, weight of m-bromobenzoic acid
$=\frac{6.1}{122} \times 201\, gm$
$=10.05\, gm$
$\%$ yield $=\frac{\text { Actual weight }}{\text { Theoretical weight }} \times 100$
$=\frac{7.8}{10.05} \times 100$
$=77.61 \,\%$
$(i)$ $C{H_3} - C \equiv C - C{H_3}$
$(ii)$ $C{H_3} - C{H_2} - C{H_2} - C{H_3}$
$(iii)$ $C{H_3} - C{H_2} - C \equiv CH$
$(iv)$ $C{H_3} - CH = C{H_2}$

${C_6}{H_6} + C{l_2}\xrightarrow{{Sunlight}}\,?$
