Question
Use the given figure to find:
(i) ∠BAD,
(ii) ∠DQB

Answer


(i) By angle sum property of ∆ADP,
∠BAD = 180° - 85° - 40° = 55°
(ii) ∠ABC = 180° - ∠ADC = 180° - 85° = 95°
(pair of opposite angles in a cyclic quadrilateral are supplementary)
By angle sum property,
∠AQB = 180° - 95° - 55°
⇒ ∠DQB = 30°

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