Answer

Therefore, displacement-time graph is shown in figure.


Average velocity for first $4\text{s}=\frac{\text{Change in displacement}}{\text{Total time takan}}$

$\text{v}=\frac{4-0}{4-0}=\frac{4\text{m}}{4\text{s}}=1\text{ms}^{-1}$

Average velocity for next 4s (i.e., in the interval of 4s to 8s), $\text{v}=\frac{4-4}{8-4}=\frac{0}{4}=0$

Average velocity for last $6\text{s}=\frac{(0-6)\text{m}}{(16-10)\text{s}}=\Big(\frac{-6}{6}\Big)=1\text{ms}^{-1}$

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