$\lambda_{1}=5000 \,\mathring A$
$\beta_{1}=\frac{ D }{ d }\left(5000 \times 10^{-10}\right)=5 \times 10^{-4} \,m$......$(I)$
$\beta_{2}=\frac{ D }{(2 d )}\left(6000 \times 10^{-10}\right)= x \text { (let) }$.....$(II)$
Divide $(II)$ and $(I)$
$\frac{\beta_{2}}{\beta_{1}}=\frac{3000 \times 10^{-10}}{5000 \times 10^{-10}}=\frac{x}{5 \times 10^{-4}}$
$x=3 \times 10^{-4} m \text { or } 0.3 \,mm$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(I)$ Moving the magnet away from the coil.
$(II)$ Moving the coil towards the magnet.
$(III)$ Rotating the coil about the vertical diameter.
$(IV)$ Rotating the coil about its axis.
An emf in the coil will be generated for the following situations.
