b
Among \(OF _2, H _2 O\) and \(OCl _2\) bond angle will depend upon electronegativity of surrounding atom as central atom is same and their hybridisation is also same

. \(OCl _2\) has unexpectedly greater angle due to bulky surrounding group \(Cl\).

Angle of \(OF _2\) is smaller than that of \(H _2 O\) as bond angle is inversely to electronegativity.

All these are \(sp ^3\) hybridized. And have \(2\) lone pairs but \(ClO _2\) has only \(3\) free electrons. Therefore, has highest bond angle.

Therefore, the bond angle order is: \(ClO _2\,>\, OCl _2\, >\, H _2 O \, >\, OF _2\).