$\mathrm{M}\left|\mathrm{M}^{2+}\right||\mathrm{X}| \mathrm{X}^{2-}$
ધારોકે $\mathrm{E}_{\left(\mathrm{M}^{2+} / \mathrm{M}\right)}^0=0.46 \mathrm{~V}$ અને $\mathrm{E}_{\left(\mathrm{x} / \mathrm{X}^{2-}\right)}^0=0.34 \mathrm{~V}$.
નીચે આપેલામાંથી ક્યું સાયું છે ?
$\mathrm{E}_{\text {cell }}^{\circ}=\mathrm{E}_{\mathrm{M} / \mathrm{M}^{+2}}^{\circ}+\mathrm{E}_{\mathrm{X} / \mathrm{X}^{-2}}^{\circ}$
$=-0.46+0.34=-0.12 \mathrm{~V}$
As $\mathrm{E}_{\text {cell }}^{\circ}$ is negative so anode becomes cathode and cathode become anode. Spontaneous reaction will be
$\mathrm{M}^{+2}+\mathrm{X}^{2-} \longrightarrow \mathrm{M}+\mathrm{X}$
$[\Lambda_{\mathrm{H}^{+}}^{\circ}=350 \,\mathrm{~S}\, \mathrm{~cm}^{2}\, \mathrm{~mol}^{-1},\Lambda_{\mathrm{CH}_{3} \mathrm{COO}^{-}}^{\circ}=50\, \mathrm{~S}\, \mathrm{~cm}^{2}\, \mathrm{~mol}^{-1}]$
$Cr\, | \,Cr^{3+}_{(0.1\,M)}\,||\, Fe^{2+}_{(0.01\, M)}\,|\, Fe$
$Cu^+ /Cu = + 0.52\, V$, $Fe^{3+} /Fe^{2+} = +0.7 7\, V$, $\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, = + 0.54\,V,$ $Ag^+ /Ag = + 0.88\,V$.
ઉપરના પોટેન્શિયલને આધારે, સૌથી પ્રબળ ઓક્સિડેશનકર્તા જણાવો.