Torque, \(\tau=p E \sin \theta\)
The work done in rotating it from an equilibrium position by an angle \(\theta\) is \(W =\)
\(\int \limits_0^\theta \tau d \theta= pE \int \limits_0^\theta \sin \theta d \theta=- pE (\cos \theta-\cos 0)= pE (1-\cos \theta)\)
$\left[\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} Nm ^{2} C ^{-2}\right] $ નો ઉપયોગ કરો