MCQ
Volume of $0.6\,\, M\,\, NaOH$ required to neutralize $30\,c{m^3}$ of $0.4\,\, M\,\, HCl$ is ............. $\mathrm{cm}^{3}$
- A$30$
- ✓$20$
- C$50$
- D$45$
✓
Answer
Correct option: B.
$20$
b
(b) $NaOH$ $HCl$
(b) $NaOH$ $HCl$
${N_1}{V_1}\; = \;{N_2}{V_2}$; $0.6 \times {V_1} = 0.4 \times 30$; ${V_1} = 20\,ml$.
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