$\mathrm{P} \propto \frac{1}{\ell}$
$\frac{\mathrm{P}_1}{\mathrm{P}_2}=\frac{\mathrm{t}_2}{\mathrm{t}_1}=\frac{15}{20}=\frac{\ell_2}{\ell_1}$
$\ell_2=\frac{3}{4} \ell_1$




$(i)$ The equivalent e.m.f. is smaller than either of the two $e.m.f.$ is
$(ii)$ The equivalent internal resistance is smaller than either of the two internal resistances